So there are only two possible ways we can get 21: We're only interested in events when we get a card that's worth either 10 (10, J, Q, K) or 11 (Ace), so we can ignore everything else. Obviously, it doesn't matter which order you draw these in, because 10 + 11 = 11 + 10. This is fairly simple – the only way you can get a score of 21 using just two cards is to get an ace (11 points) and either a 10 or a picture card (worth 10 points each). The way with logic: how can you get 21 with only two cards? And we'll look at two equivalent ways of doing it: with logic and with a tree diagram. So what's the probability of receiving this unbeatable hand? To answer this question, for simplicity's sake we'll assume that the cards are coming from a full, standard pack. If you're dealt this hand, it's impossible for you to lose (although you could tie). To be 'dealt a blackjack' means that the first two cards that you're given add up to 21, and you're done without needing any more cards.
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